document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41471>Question 41471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve.\r<BR>\n" );
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document.write( "m³+ 2m² - 3m = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26754 by </B><A HREF=/tutors/aboutme.mpl?userid=zeynep><B>zeynep(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zeynep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m³+ 2m² - 3m = 0  First, let's factor out m, which is the greatest common factor of all terms;\r<BR>\n" );
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document.write( "m(m^2+2m-3)\r<BR>\n" );
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document.write( "To factor (m^2+2m-3), we should find two numbers whose product is -3 and sum is 2. That would have to be -7 and 2. Putting that into our factors we gwt:\r<BR>\n" );
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document.write( "m(m-7)(m+2)<BR>\n" );
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