document.write( "Question 376072: Hello, can you please help me with the following equations. I am totally lost and still cannot grasp this. Could you please show the steps to getting the answer as well as I will use this as my study references.Thank you so much. \r
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document.write( "1. 5x + 3 < -2\r
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document.write( "2. 6x – 5 greater then or equal to -17\r
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document.write( "3. -9x + 4 less then or equal to -14 \r
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document.write( "4. 9( x – 3 ) greater then or equal to -9 \r
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document.write( "5. 5(x – 2) greater then or equal to 3(x + 2)
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Algebra.Com's Answer #267502 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! you work these just like a regular equation. \n" ); document.write( "1) \n" ); document.write( "5x+3<-2 \n" ); document.write( "subtract 3 \n" ); document.write( "5x<-2-3 \n" ); document.write( "5x<-5 \n" ); document.write( "divide by 5 \n" ); document.write( "x<-1 \n" ); document.write( "2) \n" ); document.write( "6x-5>=-17 \n" ); document.write( "add 5 to both sides \n" ); document.write( "6x>=-17+5 \n" ); document.write( "6x>=-12 \n" ); document.write( "x>=-2 \n" ); document.write( "3) \n" ); document.write( "-9x+4<=-14 \n" ); document.write( "subtract 4 \n" ); document.write( "-9x<=18 \n" ); document.write( "divide by -9 \n" ); document.write( "when dividing by a minus at this point the sign reverses \n" ); document.write( "x>=-2 \n" ); document.write( "4) \n" ); document.write( "9(x-3)>=-9 \n" ); document.write( "9x-27>=-9 \n" ); document.write( "add 27 \n" ); document.write( "divide by 9 \n" ); document.write( "9x>=+18 \n" ); document.write( "x>=2 \n" ); document.write( "5) \n" ); document.write( "5(x-2)>=3(x+2) \n" ); document.write( "5x-10>=3x+6 \n" ); document.write( "add 10 \n" ); document.write( "5x>=3x+6+10 \n" ); document.write( "subtract 3x \n" ); document.write( "2x>=16 \n" ); document.write( "x>=8 \n" ); document.write( "I hope that helps. \n" ); document.write( "Bob \n" ); document.write( " |