document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5267>Question 5267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I handle the 1/2 power???\r<BR>\n" );
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document.write( "(3x-5)^1/2=2\r<BR>\n" );
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document.write( "Find real solution.\r<BR>\n" );
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document.write( "Thanks  Caroline </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2675 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 1/2 power means it is a square root.<BR>\n" );
document.write( "1/3 power would me cube root,and so on.<BR>\n" );
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document.write( "(3x-5)^1/2=2<BR>\n" );
document.write( "Square root taken to the other side becomes square.<BR>\n" );
document.write( "3x-5=4<BR>\n" );
document.write( "3x=4+5<BR>\n" );
document.write( "3x=9<BR>\n" );
document.write( "x=3<BR>\n" );
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document.write( "Thus x=3.<BR>\n" );
document.write( "Hope this helps,<BR>\n" );
document.write( "good luck. </SPAN>\n" );
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