document.write( "Question 41448: A semicircle is folded to form a right circular cone so that its original base which measures 5 cm becomes the circumference of the cone base. Find :-
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document.write( "a)The diameter of the base
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document.write( "b)The curved surface area of the cone\r
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document.write( "This is what I have done\r
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document.write( "a)Diameter of the cone now = original base/2 = 5/2 = 2.5\r
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document.write( "b)Since the new diameter = 2.5 thus radius = diameter/2 = 2.5/2 = 1.25
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document.write( "Slant height = radius (is it correct ?)
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document.write( "Curved surface are of the cone
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document.write( "= PI r l (r = radius and l = slant length)
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document.write( "= 3.142 x 1.25 x 1.25
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document.write( "= 4.909375
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document.write( "= 4.9 \n" );
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Algebra.Com's Answer #26747 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE MY COMMENTS BELOW \n" ); document.write( "A semicircle is folded to form a right circular cone so that its original base which measures 5 cm becomes the circumference of the cone base. Find :- \n" ); document.write( "a)The diameter of the base \n" ); document.write( "b)The curved surface area of the cone \n" ); document.write( "This is what I have done \n" ); document.write( "a)Diameter of the cone now = original base/2 = 5/2 = 2.5...NO.. \n" ); document.write( "CIRCUMFERENCE OF SEMICIRCLE =5 = CIRCUMFERENCE OF CONE BOTTOM=PI*DCONE \n" ); document.write( "SO DCONE=5/PI....RCONE=5/2PI \n" ); document.write( "L= SLANT HEIGHT OF CONE = RADIUS OF ORIGINAL SEMICIRCLE=5/PI...(PERIMETER OF SEMICIRCLE=PI*R) \n" ); document.write( "CSA OF CONE=PI*R*L=PI*(5/2PI)*(5/PI)=25/2PI=3.98\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b)Since the new diameter = 2.5 thus radius = diameter/2 = 2.5/2 = 1.25 \n" ); document.write( "Slant height = radius (is it correct ?) \n" ); document.write( "Curved surface are of the cone \n" ); document.write( "= PI r l (r = radius and l = slant length) \n" ); document.write( "= 3.142 x 1.25 x 1.25 \n" ); document.write( "= 4.909375 \n" ); document.write( "= 4.9 \n" ); document.write( " |