document.write( "Question 376039: I Need help solving problem!!\r
\n" ); document.write( "\n" ); document.write( "Automotive Maintenance. \"Arctic Antifreeze\" is 18% alcohol and \"Frost No-More\" is 10% alcohol. How many liters of Arctic Antifreeze should be mixed with 7.5 L of Frost No-More in order to get a mixture that is 15% alcohol?
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Algebra.Com's Answer #267448 by mananth(16946)\"\" \"About 
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Automotive Maintenance. \"Arctic Antifreeze\" is 18% alcohol and \"Frost No-More\" is 10% alcohol. How many liters of Arctic Antifreeze should be mixed with 7.5 L of Frost No-More in order to get a mixture that is 15% alcohol?
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\n" ); document.write( "\"Arctic Antifreeze\" is 18% alcohol ------- x liters
\n" ); document.write( "\"Frost No-More\" is 10% alcohol. --------- 7.5 liters
\n" ); document.write( " a mixture 15% ---------------------------x+7.5 liters
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\n" ); document.write( "18*x+10*7.5 = 15(x+7.5)
\n" ); document.write( "18x+75 = 15x+112.5
\n" ); document.write( "18x-15x=112.5-75
\n" ); document.write( "3x=37.5
\n" ); document.write( "/3
\n" ); document.write( "x=12.5 liters of Arctic Antifreeze \r
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\n" ); document.write( "m.ananth@hotmail.ca
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