document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376038>Question 376038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive integers such that the sum of the second and third is forty eight more than one-fifth the smallest. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267440 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267440\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find three consecutive integers such that the sum of the second and third is forty eight more than one-fifth the smallest.\r<BR>\n" );
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document.write( "Let x = the smallest integer<BR>\n" );
document.write( "  x+1 = the 2nd integer<BR>\n" );
document.write( "  x+2 = the 3rd integer\r<BR>\n" );
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document.write( "(x+1)+(x+2) = x/5 + 48<BR>\n" );
document.write( "2x+3        = .2x +48<BR>\n" );
document.write( "       1.8x = 45<BR>\n" );
document.write( "          x = 25<BR>\n" );
document.write( "       x+1  = 26<BR>\n" );
document.write( "       x+2  = 27\r<BR>\n" );
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document.write( "The 3 consecutive integers are 25, 26, & 27. </SPAN>\n" );
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