document.write( "Question 41439: It says to complete by filling in the blank.\r
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\n" ); document.write( "\n" ); document.write( "y^2 - 13y + 36 = (y - 4)(y-___)\r
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\n" ); document.write( "\n" ); document.write( "x^2 +9x + 18 = (x+3)(x+ ____) \n" ); document.write( "

Algebra.Com's Answer #26744 by gsmani_iyer(201) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( " The answers are as under:
\n" ); document.write( " 1) $\"%28y%5E2-13y%2B36%29\"$ = (y-4)(y-9) Answer\r
\n" ); document.write( "\n" ); document.write( " 2) $\"%28x%5E2%2B9x%2B18%29\"$ = (x+3)(x+6) Answer.
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\n" ); document.write( " Just knowing the answers are not sufficient. You must know to solve such problems. In such problems, if the co-efficient of the first term is 1, then do as below:
\n" ); document.write( "1) Find out 2 such numbers product of which should be equal to the third term and the sum of the same numbers should be equal to the co-efficient of the second term i.e. middle term. Here in the first problem it is -4 and -9.
\n" ); document.write( "2) Verify the sum and product equals to the co-efficients of 2nd and 3rd terms respectively.
\n" ); document.write( "3) Now split up the middle term with those numbers as in your first example, it -4y and -9y and write it down as $\"y%5E2-9y-4y%2B36\"$
\n" ); document.write( "4) Take the first two terms and the last two terms seperately and factorise each. We get $\"y%28y-9%29-4%28y-9%29\"$ . Then we take the common factor i.e. (y-9)and factorise as (y-9)(y-4) i.e. taking the co-efficients of the common factor i.e. y and -4. That's all. I hope this is clear to you.\r
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