document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376010>Question 376010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft greater than the width. Find the length and the width of the court. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267431 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft greater than the width. Find the length and the width of the court.<BR>\n" );
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document.write( "Let w = width<BR>\n" );
document.write( "then<BR>\n" );
document.write( "w+34 = length<BR>\n" );
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document.write( "2(w + w+34) = 268<BR>\n" );
document.write( "dividing both sides by 2:<BR>\n" );
document.write( "(w + w+34) = 134<BR>\n" );
document.write( "2w+34 = 134<BR>\n" );
document.write( "2w = 100<BR>\n" );
document.write( "w = 100 ft. (width<BR>\n" );
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document.write( "Length:<BR>\n" );
document.write( "w+34 = 100+34 = 134 ft<BR>\n" );
document.write( " </SPAN>\n" );
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