document.write( "Question 375992: How man L of a 10% saline solution must be added to 40 L of a 20% saline solution to obtain a 14% saline solution? \n" ); document.write( "
Algebra.Com's Answer #267427 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! How many L of a 10% saline solution must be added to 40 L of a 20% saline solution to obtain a 14% saline solution? \n" ); document.write( ". \n" ); document.write( "Let x = amount (L) of 10% saline solution \n" ); document.write( "then\r \n" ); document.write( "\n" ); document.write( ".10x + .20(40) = .14(x+40)\r \n" ); document.write( "\n" ); document.write( ".10x + 8 = .14x + 5.6\r \n" ); document.write( "\n" ); document.write( "8 = .04x + 5.6\r \n" ); document.write( "\n" ); document.write( "2.4 = .04x\r \n" ); document.write( "\n" ); document.write( "60 liters = x\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |