document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376022>Question 376022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what rate of interest would one need in order to double one's investment in 8 years if interest is compounded daily. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267419 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume Principal = 100=P<BR>\n" );
document.write( "Amount = 200=A<BR>\n" );
document.write( "time = 8 years =n<BR>\n" );
document.write( "continuously -q=compounding term<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Compound Interest formula\r<BR>\n" );
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document.write( "i = q([A/P]1/nq - 1).\r<BR>\n" );
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document.write( "i= 365*((200/100)^(1/(8*365))-1)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "i=0.0866 = 8.66 %<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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