document.write( "Question 41451: The numerator of a fraction is 5 less than the denominator. If 1 is added to both the numerator and the denominator, the fraction would become 2/3. Find the fraction.\r
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document.write( "This is what I have done :-\r
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document.write( "Let the denominator to be n\r
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document.write( "n–5/n and now add 1 to both the numerator and the denominator
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document.write( "Therefore, n-5+1/n+1 = n-4/n+1=2/3
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document.write( "n-4 2
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document.write( "n+1 3\r
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document.write( "3(n-4) = 2(n+1)
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document.write( "3n-12 = 2n+2
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document.write( "n=12+2
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document.write( "n=14\r
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document.write( "Now n=14, thus denominator is n+1= 14 + 1 = 15 while numerator = n-4 = 14-4 = 10\r
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document.write( "Therefore, numerator = 10 and denominator = 15 but my teacher told us is 9 and 36 respectively instead. \r
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document.write( "I still don't really know where is / are my mistake(s). Please help.\r
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document.write( "Thank you so much. \n" );
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Algebra.Com's Answer #26738 by askmemath(368)![]() ![]() ![]() You can put this solution on YOUR website! You started by saying that n is the denominator \n" ); document.write( "And so the numerator is n-5\r \n" ); document.write( "\n" ); document.write( "Now when you solved you got the value of n = 14 \n" ); document.write( "which means you have to substitute this back in the orginial equation not \n" ); document.write( "\n" ); document.write( "So your numerator now is 14-5 = 9 \n" ); document.write( "When you add 1 to the numerator 9+1 = 10 \n" ); document.write( "Add 1 to the denominator = 14+1 = 15 \n" ); document.write( "Ratio = \n" ); document.write( "\n" ); document.write( "Yay!! \n" ); document.write( " |