document.write( "Question 375867: how to solve:
\n" ); document.write( "log(2x+3)+log(x-2)=2logx \n" ); document.write( "

Algebra.Com's Answer #267304 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%28%282x%2B3%29%29%2Blog%28%28x-2%29%29=2log%28%28x%29%29\"$
\n" ); document.write( " $\"log%28%282x%2B3%29%28x-2%29%29=log%28%28x%5E2%29%29\"$
\n" ); document.write( " $\"%282x%2B3%29%28x-2%29=x%5E2\"$
\n" ); document.write( " $\"2x%5E2-x-6=x%5E2\"$
\n" ); document.write( " $\"x%5E2-x-6=0\"$
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"x-3=0\"$
\n" ); document.write( " $\"x=3\"$
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\n" ); document.write( " $\"x%2B2=0\"$
\n" ); document.write( " $\"x=-2\"$
\n" ); document.write( "Verify the solutions.\r
\n" ); document.write( "\n" ); document.write( " $\"log%28%282x%2B3%29%29%2Blog%28%28x-2%29%29=2log%28%28x%29%29\"$
\n" ); document.write( " $\"log%28%282%283%29%2B3%29%29%2Blog%28%283-2%29%29=2log%28%283%29%29\"$
\n" ); document.write( " $\"log%28%289%29%29%2Blog%28%281%29%29=2log%28%283%29%29\"$
\n" ); document.write( " $\"log%28%289%29%29=log%28%289%29%29\"$
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\n" ); document.write( " $\"log%28%282x%2B3%29%29%2Blog%28%28x-2%29%29=2log%28%28x%29%29\"$
\n" ); document.write( " $\"log%28%282%28-2%29%2B3%29%29%2Blog%28%28-2-2%29%29=2log%28%28-2%29%29\"$
\n" ); document.write( "This solution is not allowed since the log function requires a positive argument.
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\n" ); document.write( " $\"highlight%28x=3%29\"$
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