document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375854>Question 375854</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A candy mixture is created with 2 types of candy, one costing $4 per pound and the other $3.50 per pound. How much of each type is needed for a  5 pound box that coast $18? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267299 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this problem you need to write two separate equations using what you know.<BR>\n" );
document.write( "First, you know that there are two types of candy and together they must total 5 pounds:<BR>\n" );
document.write( "A + B = 5<BR>\n" );
document.write( "This can be rewritten as A = 5 - B.<BR>\n" );
document.write( "Second, you know that candy A costs $4 per pound and candy B costs $3.50 per pound and together they must total $18:<BR>\n" );
document.write( "4A + 3.50B = 18<BR>\n" );
document.write( "Now you can plug in the rewritten first equation into the second equation and solve for B:<BR>\n" );
document.write( "4A + 3.50B = 18<BR>\n" );
document.write( "4(5 - B) + 3.50B = 18<BR>\n" );
document.write( "20 - 4B + 3.50B = 18<BR>\n" );
document.write( "20 - 0.5B = 18<BR>\n" );
document.write( "-0.5B = -2<BR>\n" );
document.write( "B = 4<BR>\n" );
document.write( "So you need 4 pounds of candy B (at $3.50 per pound).  Since you need 5 pounds total, this means you need only 1 pound of candy A (at $4 per pound). </SPAN>\n" );
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