document.write( "Question 375832: Please help.
\n" ); document.write( "Write an eqution of the line containing the given point and parallel to the given line. Express your answer in y = mx+b.\r
\n" ); document.write( "\n" ); document.write( "(2,4); x +6y=5
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Algebra.Com's Answer #267291 by jessica43(140)\"\" \"About 
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For two lines to be parallel, they must have the same slopes. So first we need to rewrite the given line in the formula of y = mx + b:
\n" ); document.write( "x + 6y = 5
\n" ); document.write( "6y = 5 - x
\n" ); document.write( "y = 5/6 - (1/6)x
\n" ); document.write( "Now that it is written in the correct formula, we can see that m = -1/6, which is the slope of this line. So our line must have this same slope.
\n" ); document.write( "Now we need to plug in what we know (the slope and the point (2,4)) into the y = mx + b formula:
\n" ); document.write( "y = mx + b
\n" ); document.write( "4 = (-1/6)(2) + b
\n" ); document.write( "Now solve for b:
\n" ); document.write( "4 = (-1/6)(2) + b
\n" ); document.write( "4 = (-2/6) + b
\n" ); document.write( "26/6 = b
\n" ); document.write( "So your equation of the line is y = (-1/6)x + 26/6
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