document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41417>Question 41417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been given the following problem and can't seem to figure out the answer:\r<BR>\n" );
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document.write( "You are given triangle abc, and and abc in that triangle is a right angle.<BR>\n" );
document.write( "You are also given pqrs is a rectangle inside the triangle, so that ps is parallel to ab. This problem is trying to prove that (PQ) squared is equal to AQ x BR </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26728 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have been given the following problem and can't seem to figure out the answer:<BR>\n" );
document.write( "You are given triangle abc, and and abc<BR>\n" );
document.write( "NO NOT CORRECT ACB IS THE RIGHT ANGLE.<BR>\n" );
document.write( " in that triangle is a right angle.<BR>\n" );
document.write( "You are also given pqrs is a rectangle inside the triangle, so that ps is parallel to ab. This problem is trying to prove that (PQ) squared is equal to AQ x BR<BR>\n" );
document.write( "HOPE YOU GOT THE FIGURE WITH YOU...P IS AC,S IS ON BC AND Q & R ARE ON AB. ANGLE ACB=90,OTHER ANGLES ARE A AND B<BR>\n" );
document.write( "PS IS || TO AB...GIVEN<BR>\n" );
document.write( "BC IS TRANVERSAL<BR>\n" );
document.write( "HENCE ANGLE CSP=ANGLE CBA=B.........CORRESPONDING ANGLES<BR>\n" );
document.write( "PCS IS RIGHT ANGLED TRIANGLE AT C .HENCE <BR>\n" );
document.write( "ANGLE CPS =90-ANGLE CSP =90-B<BR>\n" );
document.write( "ANGLE APQ + ANGLE QPS + ANGLE CPS =180<BR>\n" );
document.write( "ANGLE APQ =180-90-(90-B)=180-90-90+B=B<BR>\n" );
document.write( "HENCE IN TRIANGLES APQ AND SBR,WE HAVE<BR>\n" );
document.write( "ANGLE APQ =B = ANGLE SBR...PROVED ABOVE<BR>\n" );
document.write( "ANGLE AQP=90=ANGLE SRB...PQRS IS A RECTANGLE<BR>\n" );
document.write( "HENCE THE 2 TRIANGLES ARE SIMILAR<BR>\n" );
document.write( "SO<BR>\n" );
document.write( "AQ/SR=PQ/BR<BR>\n" );
document.write( "BUT PQ=SR .....PQRS IS RECTANGLE<BR>\n" );
document.write( "SO<BR>\n" );
document.write( "AQ/PQ=PQ/BR<BR>\n" );
document.write( "AQ*BR=PQ^2 </SPAN>\n" );
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