document.write( "Question 375806: mother is 4 times as old as MAy. 5 years ago, she was 7 times as old as may. how old is each 2 years from now. \n" ); document.write( "
Algebra.Com's Answer #267272 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Let x represent May's age. Then the mother's age would be represented by 4x
\n" ); document.write( "5 years ago, the mother was 7 times as old as May***
\n" ); document.write( "4x - 5 = 7(x-5)
\n" ); document.write( "solving for x
\n" ); document.write( "4x - 5 = 7x - 35
\n" ); document.write( "30 = 3x
\n" ); document.write( "10 = x, May's age NOW. the mother is NOW 40 (4*10)
\n" ); document.write( "how old is each 2 years from now
\n" ); document.write( "May is 12 and the mother is 42
\n" ); document.write( "CHECKING OUR ANSWER
\n" ); document.write( "5 years ago, the mother was 7 times as old as May***
\n" ); document.write( "35 = 7*5 \n" ); document.write( "
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