document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375775>Question 375775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve:\r<BR>\n" );
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document.write( "a^2-6a-27=0\r<BR>\n" );
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document.write( "help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267226 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2-6x-27=0<BR>\n" );
document.write( "To solve this problem you need to factor the trinomial, which is the opposite of the FOIL method. The factors will have this form:<BR>\n" );
document.write( "(x A)(x B)<BR>\n" );
document.write( "where A and B will be the factors of the third term (-27). The factors of -27 are: -1, 1, -3, 3,-9, 9, -27, and 27. So these are our possibilities of A and B: -1&27, 1&-27, -3&9, 3&-9.<BR>\n" );
document.write( "Now, we need to see which of these combinations, when added, will equal -6 (since the second term of our trinomial is -6x).<BR>\n" );
document.write( "The only combination that could equal -6 when added is -9 and 3.<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "x^2 - 6x - 27 = 0<BR>\n" );
document.write( "(x-9)(x+3)= 0<BR>\n" );
document.write( "So for this to equal zero, x = 9 or x = -3.<BR>\n" );
document.write( "Your answers are x = 9 and x = -3. </SPAN>\n" );
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