document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41424>Question 41424</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the exact value of tan 15 degrees WITHOUT USING TABLES OR A CALCULATOR. be sure to show your work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26720 by </B><A HREF=/tutors/aboutme.mpl?userid=zeynep><B>zeynep(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zeynep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you can either draw a triangle of 15-75-90 degrees and show on it, or use <BR>\n" );
document.write( "tan(a-b) formula.\r<BR>\n" );
document.write( "\n" );
document.write( "I will use the second approach.\r<BR>\n" );
document.write( "\n" );
document.write( "tan(a-b)=(tana-tanb)/(1+tana.tanb)<BR>\n" );
document.write( "tan15=tan(60-45)=(tan60-tan45)/(1+tan60.tan45)=(sqrt3-1)/(1+sqrt3.1)<BR>\n" );
document.write( "=(sqrt3-1)/(1+sqrt3) (now to make the denominator a rational number, we will multiply it with its conjugate;\r<BR>\n" );
document.write( "\n" );
document.write( "=(sqrt3-1)(sqrt3-1)/(1+sqrt3)(sqrt3-1)=(sqrt3-1)^2/2\r<BR>\n" );
document.write( "\n" );
document.write( "I hope it helps; I would have loved to solve by drawing the triangle, too however I do not know how to draw it here.If there is something you cannot understand, let me know!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );