document.write( "Question 375744: mother's age is 2 more than 5 times the age of her daughter now. two years ago, she was 7 times as old as her daughter. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #267198 by mananth(16946)\"\" \"About 
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let daughter's age = x now
\n" ); document.write( "mother's age = 5x+2
\n" ); document.write( "..
\n" ); document.write( "Agea 2 years ago
\n" ); document.write( "daughter = x-2
\n" ); document.write( "mother = 5x+2-2=5x
\n" ); document.write( "...
\n" ); document.write( "5x=7(x-2)
\n" ); document.write( "5x=7x-14
\n" ); document.write( "-5x
\n" ); document.write( "0=2x-14
\n" ); document.write( "+14
\n" ); document.write( "2x=14
\n" ); document.write( "/2
\n" ); document.write( "x=7 daughter's age now
\n" ); document.write( "mother's age = 5x+2 = 5*7 +2= 37
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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