document.write( "Question 375744: mother's age is 2 more than 5 times the age of her daughter now. two years ago, she was 7 times as old as her daughter. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #267198 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let daughter's age = x now \n" ); document.write( "mother's age = 5x+2 \n" ); document.write( ".. \n" ); document.write( "Agea 2 years ago \n" ); document.write( "daughter = x-2 \n" ); document.write( "mother = 5x+2-2=5x \n" ); document.write( "... \n" ); document.write( "5x=7(x-2) \n" ); document.write( "5x=7x-14 \n" ); document.write( "-5x \n" ); document.write( "0=2x-14 \n" ); document.write( "+14 \n" ); document.write( "2x=14 \n" ); document.write( "/2 \n" ); document.write( "x=7 daughter's age now \n" ); document.write( "mother's age = 5x+2 = 5*7 +2= 37 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |