document.write( "Question 41432This question is from textbook
\n" ); document.write( ": This question is very confusing. I don't even know where to start.\r
\n" ); document.write( "\n" ); document.write( "5x/2 - y = 9/10
\n" ); document.write( "3x/4 + 5y/6 = 2/3
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Algebra.Com's Answer #26719 by rajagopalan(174)\"\" \"About 
You can put this solution on YOUR website!
The steps are simple & easy.. see this
\n" ); document.write( "5x/2 - y = 9/10 ..eqn 1
\n" ); document.write( "3x/4 + 5y/6 = 2/3..eqn 2\r
\n" ); document.write( "\n" ); document.write( "multiply eqn 1 by 10
\n" ); document.write( "you get
\n" ); document.write( "25x-10y = 9 ..eqn 3
\n" ); document.write( "multiply eqn 2 by 12
\n" ); document.write( "9x+10y=8\r
\n" ); document.write( "\n" ); document.write( "now it is simple
\n" ); document.write( "25x-10y = 9
\n" ); document.write( "9x+10y=8
\n" ); document.write( "add both 34x=17 (y is eliminated)
\n" ); document.write( "x=1/2
\n" ); document.write( "then resub this in eqn 3
\n" ); document.write( "you get y=7/20\r
\n" ); document.write( "\n" ); document.write( "verify
\n" ); document.write( "5x/2-y=5/4-7/20=25/20 - 7/20=18/20=9/10
\n" ); document.write( "and
\n" ); document.write( "3x/4+5y/6=3/8+35/120=45/120+35/120=80/120=8/12=2/3
\n" ); document.write( "Cool\r
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