document.write( "Question 375712: (2w+i)/(w-i) = (3w+4i)/(w+3i)\r
\n" ); document.write( "\n" ); document.write( "I have tried solving this by bringing one side over to the other, making a common denominator, and subtracting, and setting it equal to zero, but then I get stuck. There must be some trick to this. I appreciate you looking at this problem. =)
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Algebra.Com's Answer #267179 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"%282w%2Bi%29%2F%28w-i%29+=+%283w%2B4i%29%2F%28w%2B3i%29\". Cross-multiply to get
\n" ); document.write( "\"%282w%2Bi%29%28w%2B3i%29=+%283w%2B4i%29%28w-i%29+\",
\n" ); document.write( "\"2w%5E2+%2B+6iw+%2B+iw+%2B+3i%5E2+=+3w%5E2+-+3iw+%2B+4iw+-+4i%5E2\", or
\n" ); document.write( "\"2w%5E2+%2B7iw+-+3+=+3w%5E2+%2B+iw+%2B+4\", or
\n" ); document.write( "\"0+=+w%5E2+-+6iw+%2B+7\",
\n" ); document.write( "0 = (w -7i )(w + i), giving
\n" ); document.write( "w = 7i or w = -i. Since none of these values make the denominators of the original equation equal to zero, these are the final answers.
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