document.write( "Question 375717: nothing like the examples . . .y^2-12y+6x+30=0 . . find vertex, focus and directrix of the parabola . . y^2-12y+30=-6x . .now I can not figure out how to factor it and solve therest. \n" ); document.write( "
Algebra.Com's Answer #267176 by robertb(5830)\"\" \"About 
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\"y%5E2-12y%2B6x%2B30=0\",
\n" ); document.write( "\"y%5E2-12y+=+-6x+-+30\",
\n" ); document.write( "\"y%5E2-12y+%2B36=-6x-30+%2B+36\",
\n" ); document.write( "\"%28y-6%29%5E2+=+-6%28x+-+1%29\". The vertex is (h,k) = (1,6). (The parabola has axis parallel to the x-axis, and opens to the left.)
\n" ); document.write( "The focus: -4c = -6, or c = 3/2. Point-wise, the focus is (-1/2, 6).
\n" ); document.write( "The directrix is the the vertical line x = 1 + 3/2, or x = 5/2.
\n" ); document.write( "(The coordinates of the latus recta are (-1/2, 9) and (-1/2, 3).)
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