document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375718>Question 375718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(9)^(x-1)=81^(2x+1) . . I am taking a online course and it is tough sometimes to try and teach urself . . any takers on expaling how i can solve this? Also, Log(1-5x)=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267172 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given equation is equivalent to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E2+=+1-5x ALIGN=MIDDLE  ALT=\"10%5E2+=+1-5x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or<BR>\n" );
document.write( "100 = 1 - 5x,<BR>\n" );
document.write( "5x = 1 - 100,<BR>\n" );
document.write( "5x = -99,<BR>\n" );
document.write( "x = -99/5.  This value satisfies the original equation, so it is the final answer. </SPAN>\n" );
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