document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375680>Question 375680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the areas of two circles is 612pi square meters. Find the length of a radius of the smaller circle if one of them is 4 times as long as the other. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267156 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the smaller circle radius be r m<BR>\n" );
document.write( "larger circle radius = 4r m<BR>\n" );
document.write( "...<BR>\n" );
document.write( "area of smaller circle +area of larger circle = 612 pi<BR>\n" );
document.write( "pi*r^2 + pi*(4r)^2= 612*pi<BR>\n" );
document.write( "pi(r^2+16r^2)=612*pi<BR>\n" );
document.write( "/pi<BR>\n" );
document.write( "17r^2= 612<BR>\n" );
document.write( "/17<BR>\n" );
document.write( "r^2= 612/17<BR>\n" );
document.write( "r^2= 36<BR>\n" );
document.write( "r=6 m the radius of smaller circle.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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