document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41407>Question 41407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 9:00 a.m. a truck leaves the truck yard and travels west at a rate of 45 mi/hr. Two hours later, a second truck leaves along the same route, traveling at 55 mi/hr. When will the second truck catch up to the first? \r<BR>\n" );
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document.write( "Thank you!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26715 by </B><A HREF=/tutors/aboutme.mpl?userid=rajagopalan><B>rajagopalan(174)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rajagopalan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rajagopalan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start time of truck 1 = 9<BR>\n" );
document.write( "start time of truck 2 = 11<BR>\n" );
document.write( "Position of truck 1 at 11 am = 45*2 = 90 km apart<BR>\n" );
document.write( "speed of truck 2 =55<BR>\n" );
document.write( "speed of truck 1 =45<BR>\n" );
document.write( "Apprach velocity = 55-45 = 10 mph<BR>\n" );
document.write( "So to cover 90 miles time needed = 90/10=9 hours<BR>\n" );
document.write( "Second truck will catch up / overtake  1st truck at 11+9 = 20 hours <BR>\n" );
document.write( "or (08:00 pm)on the same day.<BR>\n" );
document.write( "Cheers!\r<BR>\n" );
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