document.write( "Question 375655: The length of a rectangle is 15 cm more than its width. A second rectangle whose perimeter is 72 cm is 5 cm wider but 2 cm shorter than the first rectangle. What are the dimensions of each rectangle? \n" ); document.write( "
Algebra.Com's Answer #267129 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
FIRST RECTANGLE
\n" ); document.write( "let x be the width
\n" ); document.write( "length = x+15
\n" ); document.write( "...
\n" ); document.write( "SECOND RECTANGLE
\n" ); document.write( "5 cm wider = x+5
\n" ); document.write( "2cm shorter = x+15-2=x+13
\n" ); document.write( "..
\n" ); document.write( "2*(l+w)=perimeter
\n" ); document.write( "2*((x+5)+(x+13))=72
\n" ); document.write( "2*(x+5+x+13)=72
\n" ); document.write( "2*(2x+18)=72
\n" ); document.write( "divide by 2
\n" ); document.write( "2x+18= 72/2
\n" ); document.write( "2x+18=36
\n" ); document.write( "-18 -18
\n" ); document.write( "2x+18=18=36-18
\n" ); document.write( "2x=18
\n" ); document.write( "/2
\n" ); document.write( "x=18/2
\n" ); document.write( "x=9 the width
\n" ); document.write( "length = x+15 = 9+15=24
\n" ); document.write( "FIRST RECTANGLE
\n" ); document.write( "WIDTH 9 CM
\n" ); document.write( "LENGTH = 24
\n" ); document.write( "SECOND RECTANGLE
\n" ); document.write( "WIDTH = x+5 = 9+5=14
\n" ); document.write( "LENGTH = x+13= 9+13=22
\n" ); document.write( "...
\n" ); document.write( "CHECK
\n" ); document.write( "2*14+2*22=72
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "
\n" );