document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375606>Question 375606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Juniors boat will go 15miles per hour in still water.If he can go 12miles downstream in the same amount of time as it takes to go 9 miles upstream,what is the speed of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267104 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let speed of current be x mph<BR>\n" );
document.write( "speed of boat in still water = 15 mph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "downstream speed = x+15<BR>\n" );
document.write( "upstream speed = 15-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "downstream distance = 12 miles<BR>\n" );
document.write( "upstream distance = 9 miles.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "t= d/r<BR>\n" );
document.write( "..<BR>\n" );
document.write( "upstream time = downstream time<BR>\n" );
document.write( "12/(x+15)= 9/(15-x)<BR>\n" );
document.write( "12(15-x)=9(x+15)<BR>\n" );
document.write( "180-12x=9x+135<BR>\n" );
document.write( "21x=180-135<BR>\n" );
document.write( "21x=45<BR>\n" );
document.write( "/21<BR>\n" );
document.write( "x= 45/21<BR>\n" );
document.write( "x= 2.14 mph speed of current<BR>\n" );
document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );