document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375592>Question 375592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference of two numbers is 8. Three times the smaller number minus two times the larger number is –3. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267091 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l - s = 8,<BR>\n" );
document.write( "3s-2l = -3.<BR>\n" );
document.write( "The 1st equation becomes l = s + 8.  Substitute into the bottom equation, to get<BR>\n" );
document.write( "3s - 2(s+8) = -3, or<BR>\n" );
document.write( "3s - 2s - 16 = -3, or<BR>\n" );
document.write( "s = 13, the smaller number.<BR>\n" );
document.write( "l = 13+8 = 21, the larger number. </SPAN>\n" );
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