document.write( "Question 375581: if f(x)=2x+1 and g(x)= x-1 over 2 then f(g(x))= ? \n" ); document.write( "
Algebra.Com's Answer #267079 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=2x%2B1\" Start with the given function.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=2%28g%28x%29%29%2B1\" Plug in \"x=g%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=2%28%28x-1%29%2F2%29%2B1\" Plug in \"g%28x%29=%28x-1%29%2F2\" on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=cross%282%29%28%28x-1%29%2Fcross%282%29%29%2B1\" Cancel the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=x-1%2B1\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=x\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Note: if you show that g(f(x))=x as well, then you've shown the f and g are inverse functions of each other.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim\r
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