document.write( "Question 375574: if 3x squared - 2x + 7 = 0 then (x - 1/3) squared = ?\r
\n" ); document.write( "\n" ); document.write( "i no its a fraction, i think its a positive fraction with a denomater of 9. it might be 20/9.
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Algebra.Com's Answer #267076 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, let's complete the square.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-2x%2B7\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2-%282%2F3%29x%2B7%2F3%29\" Factor out the \"x%5E2\" coefficient \"3\". This step is very important: the \"x%5E2\" coefficient must be equal to 1.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"-2%2F3\" to get \"-1%2F3\". In other words, \"%281%2F2%29%28-2%2F3%29=-1%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "Now square \"-1%2F3\" to get \"1%2F9\". In other words, \"%28-1%2F3%29%5E2=%28-1%2F3%29%28-1%2F3%29=1%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2-%282%2F3%29x%2Bhighlight%281%2F9-1%2F9%29%2B7%2F3%29\" Now add and subtract \"1%2F9\" inside the parenthesis. Make sure to place this after the \"x\" term. Notice how \"1%2F9-1%2F9=0\". So the expression is not changed.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x%5E2-%282%2F3%29x%2B1%2F9%29-1%2F9%2B7%2F3%29\" Group the first three terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x-1%2F3%29%5E2-1%2F9%2B7%2F3%29\" Factor \"x%5E2-%282%2F3%29x%2B1%2F9\" to get \"%28x-1%2F3%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x-1%2F3%29%5E2%2B20%2F9%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2%2B3%2820%2F9%29\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2%2B20%2F3\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "So after completing the square, \"3x%5E2-2x%2B7\" transforms to \"3%28x-1%2F3%29%5E2%2B20%2F3\". So \"3x%5E2-2x%2B7=3%28x-1%2F3%29%5E2%2B20%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "So \"3x%5E2-2x%2B7=0\" is equivalent to \"3%28x-1%2F3%29%5E2%2B20%2F3=0\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's solve for \"%28x-1%2F3%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2%2B20%2F3=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x-1%2F3%29%5E2=-20%2F3\" Subtract \"20%2F3\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F3%29%5E2=%28-20%2F3%29%281%2F3%29\" Multiply both sides by \"1%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F3%29%5E2=-20%2F9\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"%28x-1%2F3%29%5E2=-20%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "So you were close. You were just off by a sign. \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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