document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375501>Question 375501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has an area of 54 square feet. if the length is 3 feet more than the width, find the dimension of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267071 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W+3<BR>\n" );
document.write( "AREA=LW<BR>\n" );
document.write( "54=(W+3)W<BR>\n" );
document.write( "54=W^2+3W<BR>\n" );
document.write( "W^2+3W-54=0<BR>\n" );
document.write( "(W-6)(W+9)=0<BR>\n" );
document.write( "W-6=0<BR>\n" );
document.write( "W=6 ANS.<BR>\n" );
document.write( "L=6+3<BR>\n" );
document.write( "L=9 ANS.<BR>\n" );
document.write( "pROOF:<BR>\n" );
document.write( "54=6*9<BR>\n" );
document.write( "54=54 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );