document.write( "Question 375523: the area of a rectangle is the product of its lenght and width, and equals 1062. If the lenght is 5 more then three times the width, find the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #267070 by checkley79(3341)\"\" \"About 
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L=3W+5
\n" ); document.write( "AREA=LW
\n" ); document.write( "1062=(3W+5)W
\n" ); document.write( "1062=3W^2+5W
\n" ); document.write( "3W^2+5W-1062=0
\n" ); document.write( "(3W+59)(W-18)=0
\n" ); document.write( "W-18=0
\n" ); document.write( "W=18 ANS. FOR THE WIDTH.
\n" ); document.write( "L=3*18+5
\n" ); document.write( "L=54+5
\n" ); document.write( "L=59 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "1062=18*54
\n" ); document.write( "1062=1062
\n" ); document.write( "
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