document.write( "Question 374977: Hello, i need help on solving this equation. I dont even know where to start.\r
\n" ); document.write( "\n" ); document.write( "t-2/t-1= t+17/t^(2)-1 - 1/t+1\r
\n" ); document.write( "\n" ); document.write( "Im kind of new at this but the problem is read: t minus 2 over t minus 1 equals t plus 17 over t squared minus 1 over t plus one. \n" ); document.write( "
Algebra.Com's Answer #267053 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"%28t-2%29%2F%28t-1%29\" = \"%28t%2B17%29%2F%28t%5E%282%29-1%29\" - \"1%2F%28t%2B1%29\"
\n" ); document.write( "Factoring (t^2-1) as the difference of squares, reveals the common denominator of (t-1)(t+1
\n" ); document.write( "\"%28t-2%29%2F%28t-1%29\" = \"%28t%2B17%29%2F%28%28t%2B1%29%28t-1%29%29\" - \"1%2F%28t%2B1%29\"
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\n" ); document.write( "Multiply thru by (t+1)(t-1) and you have:
\n" ); document.write( "(t+1)(t-2) = t + 17 - (t-1)
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\n" ); document.write( "FOIL the left side remove the brackets on the right side
\n" ); document.write( "t^2 - t - 2 = t + 17 - t + 1
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\n" ); document.write( "t^2 - t - 2 = 18
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\n" ); document.write( "t^2 - t - 2 - 18 = 0
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\n" ); document.write( "t^2 - t - 20 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-5)(x+4) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "x = -4
\n" ); document.write( "x = +5
\n" ); document.write( ":
\n" ); document.write( "You can check both solutions in the original problem \n" ); document.write( "
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