document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375331>Question 375331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a mason's helper requires 4 hours more to pave a concrete walk than it takes the mason. the two worked together for 3 hours when the mason war called away. the helper completed the job in 2 hours. how long would it take each to do the same job working alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267034 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mason does job in m hours. Helper does job in m+4 hours.<BR>\n" );
document.write( "t=time in hrs<BR>\n" );
document.write( "1/m + 1/(m+4)=(2m+4)/(m^2+4m) = 1/t<BR>\n" );
document.write( "3 * (2m+4)/(m^2+4m) = (6m+12)/(m^2+4m) = 3/t<BR>\n" );
document.write( "1 - (6m+12)/(m^2+4m) time remaining [1 - 3/t]<BR>\n" );
document.write( "2 * 1/(m+4)= 1 - (6m+12)/(m^2+4m)<BR>\n" );
document.write( "2/(m+4)=1 - (6m+12)/(m(m+4))<BR>\n" );
document.write( "2m=m^2+4m-6m-12<BR>\n" );
document.write( "m^2-4m-12=0<BR>\n" );
document.write( "(m-6)(x+2)=0<BR>\n" );
document.write( "m=6 hr<BR>\n" );
document.write( "m+4=10 hr<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );