document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=810>Question 810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the lateral area of the small cone that has a radius of 3 inches and a height of 4 inches.                 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #267 by </B><A HREF=/tutors/aboutme.mpl?userid=pushpaharan><B>pushpaharan(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pushpaharan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Surface area of cone is = (PI)*R*S + (PI)*R^2, where R- radius, S- Slant height.\r<BR>\n" );
document.write( "\n" );
document.write( "Slant height can be found using Pythagorean Theorem, where you know the height, and radius. Then slant height will be hypotenuse.<BR>\n" );
document.write( "there fore s= sqrt( h^2 + r^2) = 5\r<BR>\n" );
document.write( "\n" );
document.write( "Surface area = 75.43\r<BR>\n" );
document.write( "\n" );
document.write( "If it doesn't haVE CIRCULER LID, THEN NO NEED TO CONSIDER  (PI)*R^2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );