document.write( "Question 5221: find the real solutions.\r
\n" ); document.write( "\n" ); document.write( "(2x+5)^2-(2+5)-6=0\r
\n" ); document.write( "\n" ); document.write( "thanks Caroline
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Algebra.Com's Answer #2669 by ichudov(507)\"\" \"About 
You can put this solution on YOUR website!
I have a hunch that you forgot an 'x' and meant\r
\n" ); document.write( "\n" ); document.write( "\"%282x%2B5%29%5E2-%282x%2B5%29-6=0\"\r
\n" ); document.write( "\n" ); document.write( "use y instead of 2x+5, to get\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2-y-6+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solve it for y:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ay%5E2%2Bby%2Bc=0\" (in our case \"1y%5E2%2B-1y%2B-6+=+0\") has the following solutons:
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\n" ); document.write( " \"y%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1%29%5E2-4%2A1%2A-6=25\".
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\n" ); document.write( " Discriminant d=25 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--1%2B-sqrt%28+25+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"y%5B1%5D+=+%28-%28-1%29%2Bsqrt%28+25+%29%29%2F2%5C1+=+3\"
\n" ); document.write( " \"y%5B2%5D+=+%28-%28-1%29-sqrt%28+25+%29%29%2F2%5C1+=+-2\"
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\n" ); document.write( " Quadratic expression \"1y%5E2%2B-1y%2B-6\" can be factored:
\n" ); document.write( " \"1y%5E2%2B-1y%2B-6+=+1%28y-3%29%2A%28y--2%29\"
\n" ); document.write( " Again, the answer is: 3, -2.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1%2Ax%2B-6+%29\"

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\n" ); document.write( "\n" ); document.write( "y=3, y=-2, or, knowing that y=2x+5, you have two equations\r
\n" ); document.write( "\n" ); document.write( "2x+5 = 3, or 2x=-2, or x = -1
\n" ); document.write( "2x+5 = -2, or 2x=-7, or x = -3.5.\r
\n" ); document.write( "\n" ); document.write( "Double check my answer please.\r
\n" ); document.write( "\n" ); document.write( "Answer: x=-1, x=-3.5
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