document.write( "Question 375319: 3^-2 = (1/9)
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document.write( " I need to rewrite as a logarithm equation
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document.write( "Thanks \n" );
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Algebra.Com's Answer #266882 by Jk22(389) You can put this solution on YOUR website! log(3^-2) = log(1/9) \n" ); document.write( " \n" ); document.write( "-2*log(3) = -log(9), \n" ); document.write( " \n" ); document.write( " with the properties log(ab)=log(a)+log(b), log(1)=0, log(a^b)=b*log(a) \n" ); document.write( " |