document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375299>Question 375299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers equal 91. the first is five more than the second, and the third is two times the first. what are the three numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266880 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the second number be x<BR>\n" );
document.write( "first number = x+5<BR>\n" );
document.write( "third number = 2(x+5)<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+x+5 +2(x+5)=91<BR>\n" );
document.write( "x+x+5+2x+10=91<BR>\n" );
document.write( "4x+15=91<BR>\n" );
document.write( "-15<BR>\n" );
document.write( "4x=76<BR>\n" );
document.write( "/4<BR>\n" );
document.write( "x=19<BR>\n" );
document.write( "...<BR>\n" );
document.write( "the numbers are 19, 24, 48<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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