document.write( "Question 375325: A boat travels 80 miles upstream in a river with a current of 6 miles per hour; then it travels back down to its starting point. The total time of the trip was 4 hours. Find the speed of the boat in still water. what is the equation too? \n" ); document.write( "
Algebra.Com's Answer #266877 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let speed of boat in still water be x mph \n" ); document.write( ".. \n" ); document.write( "current speed = 6 mph. \n" ); document.write( ".. \n" ); document.write( "speed upstream = x-6 mph \n" ); document.write( "speed downstream = x+6 mph. \n" ); document.write( ".. \n" ); document.write( "t = d/r \n" ); document.write( "time upstream + time downstream = 4 hours \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "multiply by (x+6)(x-6) \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "160x= 4x^2-36 \n" ); document.write( "4x^2-160x-36=0 \n" ); document.write( "/4 \n" ); document.write( "x^2-40x-9=0 \n" ); document.write( "discriminant = 1636 \n" ); document.write( "x1=((40+sqrt(1636)))/2 \n" ); document.write( "x1=40.2 mph speed of boat in still water \n" ); document.write( "x2 will be negative so ignore \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |