document.write( "Question 375325: A boat travels 80 miles upstream in a river with a current of 6 miles per hour; then it travels back down to its starting point. The total time of the trip was 4 hours. Find the speed of the boat in still water. what is the equation too? \n" ); document.write( "
Algebra.Com's Answer #266877 by mananth(16946)\"\" \"About 
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let speed of boat in still water be x mph
\n" ); document.write( "..
\n" ); document.write( "current speed = 6 mph.
\n" ); document.write( "..
\n" ); document.write( "speed upstream = x-6 mph
\n" ); document.write( "speed downstream = x+6 mph.
\n" ); document.write( "..
\n" ); document.write( "t = d/r
\n" ); document.write( "time upstream + time downstream = 4 hours
\n" ); document.write( "\"80%2F%28x-6%29%2B80%2F%28x%2B6%29+=4\"
\n" ); document.write( "..
\n" ); document.write( "\"%2880%2A%28x%2B6%29%2B80%2A%28x-60%29%29%2F%28%28x%2B6%29%2A%28x-6%29%29=4\"
\n" ); document.write( "...
\n" ); document.write( "\"%2880x%2B480%2B80x-480%29%2F%28%28x%2B6%29%28x-6%29%29=4\"
\n" ); document.write( "...
\n" ); document.write( "\"%28160x%29%2F%28%28x%2B6%29%28x-6%29%29=4\"
\n" ); document.write( "...
\n" ); document.write( "multiply by (x+6)(x-6)
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\n" ); document.write( "..
\n" ); document.write( "160x= 4x^2-36
\n" ); document.write( "4x^2-160x-36=0
\n" ); document.write( "/4
\n" ); document.write( "x^2-40x-9=0
\n" ); document.write( "discriminant = 1636
\n" ); document.write( "x1=((40+sqrt(1636)))/2
\n" ); document.write( "x1=40.2 mph speed of boat in still water
\n" ); document.write( "x2 will be negative so ignore
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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