document.write( "Question 375309: A group of hikers is to travel x km by bus at an average speed of 48 km/h to an unknown destination. They then plan to walk back along the same route at an average speed of 4.8 km/h and to arrive back 24 hours after setting out in the bus. If they allow 2 h for lunch and rest, how far must the bus take them? \n" ); document.write( "
Algebra.Com's Answer #266870 by mananth(16946)![]() ![]() You can put this solution on YOUR website! time taken by bus +time walking + 2hours = 24 \n" ); document.write( "... \n" ); document.write( "t= d/r \n" ); document.write( "x/48 + x/4.8 + 2 = 24 \n" ); document.write( "x/48 +x/4.8 = 24-2 \n" ); document.write( "LCD = 48 \n" ); document.write( "(x+10x)/48 = 22 \n" ); document.write( "11x=48*22 \n" ); document.write( "/11 \n" ); document.write( "x= 48*22/11 \n" ); document.write( "x=48*2 \n" ); document.write( "x=96 km is the distance they have to travel by bus \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |