document.write( "Question 375320: I am trying to come up with an algebraic equation to determine the cost of two refrigerators with good energy ratings. I found one with that will cost .1143 cents per kWh and it boasts that it uses 486 kWh per year. I want to compare it with another one I found that will cost .1143 cents per kWh. This one uses 526 kWh per year. If the purchase price of the first refrigerator is $950 and the second is $875, which one will be the better buy after 10 years?
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document.write( "I'm sorry for the long question, I hope someone out there can give me an algebraic equation for putting this all together. I'd like to use it again for other appliances in the future.''.\r
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Algebra.Com's Answer #266867 by mananth(16946)![]() ![]() You can put this solution on YOUR website! First refrigerator cost + power cost for ten years \n" ); document.write( "General Equation: \n" ); document.write( "Let the number of years run be x \n" ); document.write( "(Cx1)=950+0.1143*486*x \n" ); document.write( "(Cx)=950 + 55.55x \n" ); document.write( "Second refrigerator \n" ); document.write( "(Cx2)=875+0.1143*526*x \n" ); document.write( "(Cx2)=875+60.12x \n" ); document.write( "... \n" ); document.write( "Plug the value of x=10 for both equations to find which is a better deal.\r \n" ); document.write( "\n" ); document.write( "(Cx1)= $1505.5 \n" ); document.write( "(Cx2)= $ 1476.2 \n" ); document.write( ".. \n" ); document.write( "You decide \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |