document.write( "Question 375314: The perimeter of a rectangle is (4x^2+ 10x+20) inches and its lenght is (x^2+4x+8) inches. Find the width. \n" ); document.write( "
Algebra.Com's Answer #266866 by mananth(16946)\"\" \"About 
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Let width be w
\n" ); document.write( "2*(l+w)= perimeter
\n" ); document.write( "2*((x^2-4x+8)+w)=(4x^2+10x+20)
\n" ); document.write( "2x^2-8x+16+2w=4x^2+10x+20
\n" ); document.write( "reorganize the terms
\n" ); document.write( "4x^2-2x^2+10x+8x+20-16=2w
\n" ); document.write( "2x^2+18x+4=2w
\n" ); document.write( "/2
\n" ); document.write( "x^2+9x+2=w
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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