document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=375192>Question 375192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ship must average 22 knots to make it's 10hr run on schedule. During the first 4 hrs bad weather caused it to reduce speed to 16 knots, what should it's average speed be for the rest of the trip to maintain its schedule? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266828 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Average for the trip = 22 knots/h<BR>\n" );
document.write( "time = 10 hours<BR>\n" );
document.write( "distance = 10*22=220 miles.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "First 4 hours<BR>\n" );
document.write( "rate = 16 knots/h<BR>\n" );
document.write( "distance = 64 miles.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "distance to cover in balance  6 hours = 220-64<BR>\n" );
document.write( "=156 miles<BR>\n" );
document.write( "..<BR>\n" );
document.write( "time = 6 hours<BR>\n" );
document.write( "..<BR>\n" );
document.write( "rate = d/t<BR>\n" );
document.write( "rate = 156/6<BR>\n" );
document.write( "rate = 26 knots/h<BR>\n" );
document.write( "This should be the speed to be on time.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );