document.write( "Question 375177: How many ounces of pure gold that costs $450 an ounce must be mixed with 75 ounces of an alloy that costs $200 an ounce to make an alloy that costs $300 an ounce? \n" ); document.write( "
Algebra.Com's Answer #266801 by mananth(16946) You can put this solution on YOUR website! let x ounce of gold be mixed.\r \n" ); document.write( "\n" ); document.write( "gold $450 -------- x ounce \n" ); document.write( "alloy $200--------75 ounce \n" ); document.write( "Mix $300----------(x+75) \n" ); document.write( "... \n" ); document.write( "450x + 200*75 = 300(x+75) \n" ); document.write( "450x+15000=300x+22500 \n" ); document.write( "450x-300x=22500-15000 \n" ); document.write( "150x=7500 \n" ); document.write( "/150 \n" ); document.write( "x=7500/150 \n" ); document.write( "x=50 ounces of pure gold. \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |