document.write( "Question 375177: How many ounces of pure gold that costs $450 an ounce must be mixed with 75 ounces of an alloy that costs $200 an ounce to make an alloy that costs $300 an ounce? \n" ); document.write( "
Algebra.Com's Answer #266801 by mananth(16946)\"\" \"About 
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let x ounce of gold be mixed.\r
\n" ); document.write( "\n" ); document.write( "gold $450 -------- x ounce
\n" ); document.write( "alloy $200--------75 ounce
\n" ); document.write( "Mix $300----------(x+75)
\n" ); document.write( "...
\n" ); document.write( "450x + 200*75 = 300(x+75)
\n" ); document.write( "450x+15000=300x+22500
\n" ); document.write( "450x-300x=22500-15000
\n" ); document.write( "150x=7500
\n" ); document.write( "/150
\n" ); document.write( "x=7500/150
\n" ); document.write( "x=50 ounces of pure gold.
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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