document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=374630>Question 374630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A girl is 6 years younger than her oldest  brother. The product of their ages is 135. Find their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #266783 by </B><A HREF=/tutors/aboutme.mpl?userid=corncob><B>corncob(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=corncob><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=266783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay to do this you will need to set up a simple equation and give out variables.\r<BR>\n" );
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document.write( "Girls age = x-6<BR>\n" );
document.write( "Brother's age= *\r<BR>\n" );
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document.write( "the you will take those 2 and add them and place them equil to 135 like so:\r<BR>\n" );
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document.write( "x-6+x=135<BR>\n" );
document.write( "2x-6+6=135+6<BR>\n" );
document.write( "2x=141<BR>\n" );
document.write( "2x/2=141/2<BR>\n" );
document.write( "x=70.5\r<BR>\n" );
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document.write( "The brothers age would be 70.5 then and the girl's would be 64.5 </SPAN>\n" );
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