document.write( "Question 41154: 2x+(k-1)y=6
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Algebra.Com's Answer #26677 by vidhyak(98)\"\" \"About 
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2x + (k-1)y =6 ........eq1
\n" ); document.write( "3x + (2k+1)y =9 ........eq2\r
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\n" ); document.write( "\n" ); document.write( "Multiply eq1 by 3 and eq2 by 2 and subtract\r
\n" ); document.write( "\n" ); document.write( " 6x + 3(k-1)y = 18
\n" ); document.write( "-6x - 2(2k+1)y = -18\r
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\n" ); document.write( "\n" ); document.write( "3(k-1)y - 2(2k+1)y = 0
\n" ); document.write( "y(3(k-1) - 2(2k+1)) = 0
\n" ); document.write( "3(k-1) - 2(2k+1) = 0
\n" ); document.write( "3k - 3 - 4k - 2 = 0
\n" ); document.write( "-k -5 = 0
\n" ); document.write( "-k = 5
\n" ); document.write( "k = -5\r
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