document.write( "Question 375060: x-0.05x=19\r
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document.write( "0.2a=0.05a+3\r
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document.write( "x/x+5=2/3\r
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document.write( "3/a+1/2=11/5a\r
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document.write( "x/2=3/2x+1 \n" );
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Algebra.Com's Answer #266731 by robertb(5830) You can put this solution on YOUR website! x-0.05x=19 => 0.95x = 19 => x = 20.\r \n" ); document.write( "\n" ); document.write( "0.2a=0.05a+3 => 0.15a = 3 => a = 20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x/(x+5)=2/3 => 3x = 2(x+5) => 3x = 2x +10 => x = 10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3/a+1/2=11/5a => 3/a + 0.5 = 2.2/a =>0.8/a = -0.5 => a = -1.6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x/2=3/(2x+1) => x(2x+1) = 6 => \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |