document.write( "Question 375065: Hello everyone, finding the following question puzzling, i have not covered this before, and am trying to get a heads up for when i start my course\r
\n" ); document.write( "\n" ); document.write( "Use logarithmic differentiation to differentiate the following:
\n" ); document.write( "(i) y = 2^x (ii) y = x^x\r
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Algebra.Com's Answer #266728 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
i)\r
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\n" ); document.write( "\n" ); document.write( "\"y=2%5Ex\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28y%29=ln%282%5Ex%29\" Take the natural log of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28y%29=x%2Aln%282%29\" Pull down the exponent.\r
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\n" ); document.write( "\n" ); document.write( " ... Derive both sides\r
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\n" ); document.write( "\n" ); document.write( " ... Solve for y'\r
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\n" ); document.write( "\n" ); document.write( " ... Now plug in \"y=2%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "Note: the derivative of \"b%5Ex\" is \"b%5Ex%2Aln%28b%29\"\r
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\n" ); document.write( "\n" ); document.write( "ii)\r
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\n" ); document.write( "\n" ); document.write( "\"y=x%5Ex\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ln%28y%29=ln%28x%5Ex%29\" Take the natural log of both sides.\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ln%28y%29=x%2Aln%28x%29\" Pull down the exponent.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " ... Derive both sides\r
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\n" ); document.write( "\n" ); document.write( " ... Solve for y'\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " ... Now plug in \"y=x%5Ex\"
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