document.write( "Question 374877: If you have numbers from 1 to 999 in a bag and you pull out 10 numbers, what are the odds that 7 of those numbers will be from 700 to 999? Is there a formula for figuring this out and if there is can you send it to me? Thanks for your help. Pam \n" ); document.write( "
Algebra.Com's Answer #266655 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! If you have numbers from 1 to 999 in a bag and you pull out 10 numbers, what are the odds that 7 of those numbers will be from 700 to 999? Is there a formula for figuring this out and if there is can you send it to me? Thanks for your help. Pam\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "999 numbers \n" ); document.write( "700 to 999 is 300 numbers \n" ); document.write( "P(r) = C(n,r) * p^r * q^(n-r) \n" ); document.write( "q = 1 - p \n" ); document.write( "C(n,r) = n!/(r! * (n-r)!) \n" ); document.write( "r successes in n tries \n" ); document.write( "C(10,7) = 10!/(7! * (10 - 7)!) \n" ); document.write( "C(10,7) = 10!/(7! * 3!) \n" ); document.write( "C(10,7) = (8 * 9 * 10)/(1 * 2 * 3) \n" ); document.write( "C(10,7) = 720/6 = 120 \n" ); document.write( "p^r = (300/999)^7 \n" ); document.write( "q^(n - r) = (699/999)^3 \n" ); document.write( "P(7) = 120 * (300/999)^7 * (699/999)^3 \n" ); document.write( "0.00905329504280360257128551493191386 \n" ); document.write( "P(7) = 0.009053 rounded to 6 places \n" ); document.write( "P(7) = 0.9053 %\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |