document.write( "Question 374854: A company plans to make 10 liters of a 17% acid solution by mixing a 20% acid solution and a 15% acid solution. How much of each solution should be used. \n" ); document.write( "

Algebra.Com's Answer #266585 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x represent the amount of the more concentrated 20% solution
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document.write( "then (10L-x) would be the amount of the 15% solution
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document.write( "Mixing to form a 17% 10L solution***Amount of acid in each the equalizer
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document.write( ".20*x + .15(10L -x) = .17*10L
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document.write( "solving for x
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document.write( ".20*x + .15*10L -.15x = .17*10L
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document.write( ".05x = .02*10L
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document.write( "x = .02*10L/.05
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document.write( "x = 4L, the amount of the 20% solution.  
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document.write( "6L the amount of the 15% solution (10L-4L)
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document.write( "CHECKING our Answer
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document.write( ".20*4L + .15*6L = .8L + .9L = 1.7L = .17*10L
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